项目作者: triska

项目描述 :
Constraint Logic Programming over Integers
高级语言: Prolog
项目地址: git://github.com/triska/clpz.git
创建时间: 2016-04-17T16:56:55Z
项目社区:https://github.com/triska/clpz

开源协议:

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CLP(ℤ) — Constraint Logic Programming over Integers

This repository contains information about CLP(ℤ).

CLP(ℤ) requires SICStus Prolog.

As of April 2020, a version of this library ships with
Scryer Prolog as library(clpz).

The present implementation builds upon a decade of experience with a
precursor library which I developed for a different Prolog system.
CLP(ℤ) is the more recent and conceptually more advanced
implementation. To keep track of recent developments, use CLP(ℤ).

Current developments:

  • increase logical purity of the implementation
  • work on stronger propagation
  • correct all reported issues.
  • add new constraints.

CLP(ℤ) is being developed for inclusion in
GUPU.

An introduction to declarative integer arithmetic is available from
metalevel.at/prolog/clpz

Video: https://www.metalevel.at/prolog/videos/integer_arithmetic CLP(ℤ) video

For more information about pure Prolog, read The Power of Prolog.

Using CLP(ℤ) constraints

CLP(ℤ) is an instance of the general CLP(X) scheme, extending logic
programming with reasoning over specialised domains.

In the case of CLP(ℤ), the domain is the set of integers. CLP(ℤ)
is a generalisation of CLP(FD) as provided by SICStus Prolog.

CLP(ℤ) constraints like (#=)/2, (#\=)/2, and (#<)/2 are meant to
be used as more general alternatives for lower-level arithmetic
primitives over integers. Importantly, they can be used in all
directions
.

For example, consider a rather typical definition of n_factorial/2:

  1. n_factorial(0, 1).
  2. n_factorial(N, F) :-
  3. N #> 0,
  4. N1 #= N - 1,
  5. n_factorial(N1, F1),
  6. F #= N * F1.

CLP(ℤ) constraints allow us to quite freely exchange the order
of goals, obtaining for example:

  1. n_factorial(0, 1).
  2. n_factorial(N, F) :-
  3. N #> 0,
  4. N1 #= N - 1,
  5. F #= N * F1,
  6. n_factorial(N1, F1).

This works in all directions, for example:

  1. ?- n_factorial(47, F).
  2. 258623241511168180642964355153611979969197632389120000000000 ;
  3. false.

and also:

  1. ?- n_factorial(N, 1).
  2. N = 0 ;
  3. N = 1 ;
  4. false.

and also in the most general case:

  1. ?- n_factorial(N, F).
  2. N = 0,
  3. F = 1 ;
  4. N = F, F = 1 ;
  5. N = F, F = 2 ;
  6. N = 3,
  7. F = 6 .

The advantage of using (#=)/2 to express arithmetic equality is
clear: It is a more general alternative for lower-level predicates.

In addition to providing declarative integer arithmetic,
CLP(ℤ) constraints are also often used to solve
combinatorial tasks
with Prolog.

Example programs

This repository contains several example programs. The main predicates
are all completely pure and can be used as true relations. This means
that you can use the same program to:

  • find a single solution
  • enumerate all solutions
  • complete partially instantiated solutions
  • validate fully instantiated solutions.

To get an idea of the power, usefulness and scope of CLP(ℤ)
constraints, I recommend you work through the examples in the
following order:

  1. n_factorial.pl: Shows how to use CLP(ℤ)
    constraints for declarative integer arithmetic, obtaining very
    general programs that can be used in all directions. Declarative
    integer arithmetic is the simplest and most common use of CLP(ℤ)
    constraints. They are easy to understand and use this way, and
    often increase generality and logical purity of your code.

  2. sendmory.pl: A simple cryptoarithmetic puzzle.
    The task is to assign one of the digits 0,…,9 to each of the
    letters S,E,N,D,M,O,R and Y in such a way that the following
    calculation is valid, and no leading zeroes appear:

    1. S E N D
    2. + M O R E
    3. ---------
    4. = M O N E Y

    This example illustrates several very important concepts:

    • It is the first example that shows residual constraints for the
      most general query. They are equivalent to the original query.

    • It is good practice to separate the core relation from
      labeling/2, so that termination and determinism can be observed
      without an expensive search for concrete solutions.

    • You can use this example to illustrate that the CLP(ℤ) system is able
      to propagate many things that can also be found with human
      reasoning. For example, due to the nature of the above calculation and
      the prohibition of leading zeroes, M is necessarily 1.

  3. sudoku.pl: Uses CLP(ℤ) constraints to model and
    solve a simple and well-known puzzle. This example is well suited
    for understanding the impact of different propagation
    strengths
    : Use it to compare all_different/1 all_distinct/1
    on different puzzles:

    Sudoku with all_different/1 Sudoku with all_distinct/1

    The small dots in each cell indicate how many elements are pruned
    by different consistency techniques. In many Sudoku puzzles,
    using all_distinct/1 makes labeling unnecessary. Does this mean that
    we can forget all_different/1 entirely?

    Video: https://www.metalevel.at/prolog/videos/sudoku

  4. magic_square.pl: CLP(ℤ) formulation of magic
    squares
    . This is a good
    example to learn about symmetry breaking constraints: Consider how
    you can eliminate solutions that are rotations, reflections etc. of
    other solutions, by imposing suitable further constraints. For example,
    the following two solutions are essentially identical, since one can be
    obtained from the other by reflecting elements along the main diagonal:

    Magic square solution Magic square transposed

    Can you impose additional constraints so that you get only a single
    solution in such cases, without losing any solutions that do not
    belong to the same equivalence class? How many solutions are there
    for N=4 that are unique up to isomorphism?

  5. magic_hexagon.pl: Uses CLP(ℤ) to describe a
    magic hexagon of
    order 3. The task is to place the integers 1,…,19 in the following
    grid so that the sum of all numbers in a straight line (there are lines
    of length 3, 4 and 5) is equal to 38. One solution of this task is shown
    in the right picture:

    Magic hexagon grid Magic hexagon solution

    This is an example of a task that looks very simple at first, yet
    is almost impossibly hard to solve manually. It is easy to solve
    with CLP(ℤ) constraints though. Use the constraint solver to show
    that the solution of this task is unique up to isomorphism.

  6. n_queens.pl: Model the so-called N-queens
    puzzle
    with
    CLP(ℤ) constraints. This example is a good candidate to experiment
    with different search strategies, specified as options of
    labeling/2. For example, using the labeling strategy ff, you
    can easliy find solutions for 100 queens and more. Sample solutions
    for 8 and 50 queens:

    Solution for 8 queens Solution for 50 queens

    Try to find solutions for larger N. Reorder the variables so that
    ff breaks ties by selecting more central variables first.

    Video: https://www.metalevel.at/prolog/videos/n_queens

  7. knight_tour.pl: Closed Knight’s Tour using
    CLP(ℤ) constraints. This is an example of using a more complex
    global constraint called circuit/1. It shows how a problem
    can be transformed so that it can be expressed with a global
    constraint. Sample solutions, using an 8x8 and a 16x16 board:

    Closed knight's tour on an 8x8 board Closed knight's tour on a 16x16 board

    Decide whether circuit/1 can also be used to model tours that are
    not necessarily closed. If not, why not? If possible, do it.

  8. tasks.pl: A task scheduling example, using the
    cumulative/2 global constraint. The min/1 labeling option is
    used to minimize the total duration.

    Task scheduling

Animations

When studying Prolog and CLP(ℤ) constraints, it is often very useful
to show animations of search processes. An instructional example:

N-queens animation: This
visualizes the search process for the N-queens example.

You can use similar PostScript instructions to create custom
animations
for
other examples.

A limited alternative: Low-level integer arithmetic

Suppose for a moment that CLP(ℤ) constraints were not available in
your Prolog system, or that you do not want to use them. How do we
formulate n_factorial/2 with more primitive integer arithmetic?

In our first attempt, we simply replace the declarative CLP(ℤ)
constraints by lower-level arithmetic predicates and obtain:

  1. n_factorial(0, 1).
  2. n_factorial(N, F) :-
  3. N > 0,
  4. N1 is N - 1,
  5. F is N * F1,
  6. n_factorial(N1, F1).

Unfortunately, this does not work at all, because lower-level
arithmetic predicates are moded: This means that their arguments
must be sufficiently instantiated at the time they are invoked.
Therefore, we must reorder the goals and — somewhat
annoyingly — change this for example to:

  1. n_factorial(0, 1).
  2. n_factorial(N, F) :-
  3. N > 0,
  4. N1 is N - 1,
  5. n_factorial(N1, F1),
  6. F is N * F1.

Naive example queries inspired more by functional than by
relational thinking may easily mislead us into believing that this
version is working correctly:

  1. ?- n_factorial(6, F).
  2. F = 720 ;
  3. false.

Another example:

  1. ?- n_factorial(3, F).
  2. F = 6 ;
  3. false.

But what about more general queries? For example:

  1. ?- n_factorial(N, F).
  2. N = 0,
  3. F = 1 ;
  4. ERROR: n_factorial/2: Arguments are not sufficiently instantiated

Unfortunately, this version thus cannot be directly used to enumerate
more than one solution, which is another severe drawback in comparison
with the more general version.

You can make the deficiency a lot worse by arbitrarily adding
a !/0 somewhere. Using !/0 is a quite reliable way to destroy
almost all declarative properties of your code in most cases, and this
example is no exception:

  1. n_factorial(0, 1) :- !.
  2. n_factorial(N, F) :-
  3. N > 0,
  4. N1 is N - 1,
  5. n_factorial(N1, F1),
  6. F is N * F1.

This version appears in several places. The fact that the following
interaction incorrectly tells us that there is exactly one solution of
the factorial relation is apparently no cause for concern there:

  1. ?- n_factorial(N, F).
  2. N = 0,
  3. F = 1.

Zero and one are the only important integers in any case, if you are
mostly interested in programming at a very low level.

For more usable and general programs, I therefore recommend you stick
to CLP(ℤ) constraints for integer arithmetic. You can place pure
goals in any order without changing the declarative meaning of your
program, just as you would expect from logical conjunction. For
example:

  1. n_factorial(0, 1).
  2. n_factorial(N, F) :-
  3. N #> 0,
  4. N1 #= N - 1,
  5. n_factorial(N1, F1),
  6. F #= N * F1.

Reordering pure goals can change termination properties, but it
cannot incorrectly lead to failure where there is in fact a solution.
Therefore, we get with the above CLP(ℤ) version for example:

  1. ?- n_factorial(N, 3).
  2. <loops>

And now we can reason completely declaratively about the code: Knowing
that (a) CLP(ℤ) constraints are pure and can thus be reordered
quite liberally and (b) that posting CLP(ℤ) constraints always
terminates
, we know that placing CLP(ℤ) constraints earlier can at
most improve, never worsen the desirable termination properties.

Therefore, we change the definition to the version shown initially:

  1. n_factorial(0, 1).
  2. n_factorial(N, F) :-
  3. N #> 0,
  4. N1 #= N - 1,
  5. F #= N * F1,
  6. n_factorial(N1, F1).

The sample query now terminates:

  1. ?- n_factorial(N, 3).
  2. false.

Using CLP(ℤ) constraints has allowed us to improve the termination
properties of this predicate by purely declarative reasoning.

Acknowledgments

I am extremely grateful to:

Ulrich Neumerkel, who
introduced me to constraint logic programming.

Nysret Musliu, my thesis
advisor, whose interest in combinatorial tasks and constraint
satisfaction highly motivated me to work in this area.

Mats Carlsson, the designer and
main implementor of SICStus Prolog and its superb CLP(FD)
library

which spawned my interest in constraints.